3.344 \(\int \frac {x^3}{(a+b x)^{3/2}} \, dx\)
Optimal. Leaf size=66 \[ \frac {2 a^3}{b^4 \sqrt {a+b x}}+\frac {6 a^2 \sqrt {a+b x}}{b^4}-\frac {2 a (a+b x)^{3/2}}{b^4}+\frac {2 (a+b x)^{5/2}}{5 b^4} \]
[Out]
-2*a*(b*x+a)^(3/2)/b^4+2/5*(b*x+a)^(5/2)/b^4+2*a^3/b^4/(b*x+a)^(1/2)+6*a^2*(b*x+a)^(1/2)/b^4
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Rubi [A] time = 0.02, antiderivative size = 66, normalized size of antiderivative = 1.00,
number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used =
{43} \[ \frac {2 a^3}{b^4 \sqrt {a+b x}}+\frac {6 a^2 \sqrt {a+b x}}{b^4}-\frac {2 a (a+b x)^{3/2}}{b^4}+\frac {2 (a+b x)^{5/2}}{5 b^4} \]
Antiderivative was successfully verified.
[In]
Int[x^3/(a + b*x)^(3/2),x]
[Out]
(2*a^3)/(b^4*Sqrt[a + b*x]) + (6*a^2*Sqrt[a + b*x])/b^4 - (2*a*(a + b*x)^(3/2))/b^4 + (2*(a + b*x)^(5/2))/(5*b
^4)
Rule 43
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])
Rubi steps
\begin {align*} \int \frac {x^3}{(a+b x)^{3/2}} \, dx &=\int \left (-\frac {a^3}{b^3 (a+b x)^{3/2}}+\frac {3 a^2}{b^3 \sqrt {a+b x}}-\frac {3 a \sqrt {a+b x}}{b^3}+\frac {(a+b x)^{3/2}}{b^3}\right ) \, dx\\ &=\frac {2 a^3}{b^4 \sqrt {a+b x}}+\frac {6 a^2 \sqrt {a+b x}}{b^4}-\frac {2 a (a+b x)^{3/2}}{b^4}+\frac {2 (a+b x)^{5/2}}{5 b^4}\\ \end {align*}
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Mathematica [A] time = 0.02, size = 45, normalized size = 0.68 \[ \frac {2 \left (16 a^3+8 a^2 b x-2 a b^2 x^2+b^3 x^3\right )}{5 b^4 \sqrt {a+b x}} \]
Antiderivative was successfully verified.
[In]
Integrate[x^3/(a + b*x)^(3/2),x]
[Out]
(2*(16*a^3 + 8*a^2*b*x - 2*a*b^2*x^2 + b^3*x^3))/(5*b^4*Sqrt[a + b*x])
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fricas [A] time = 0.45, size = 51, normalized size = 0.77 \[ \frac {2 \, {\left (b^{3} x^{3} - 2 \, a b^{2} x^{2} + 8 \, a^{2} b x + 16 \, a^{3}\right )} \sqrt {b x + a}}{5 \, {\left (b^{5} x + a b^{4}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x^3/(b*x+a)^(3/2),x, algorithm="fricas")
[Out]
2/5*(b^3*x^3 - 2*a*b^2*x^2 + 8*a^2*b*x + 16*a^3)*sqrt(b*x + a)/(b^5*x + a*b^4)
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giac [A] time = 1.10, size = 61, normalized size = 0.92 \[ \frac {2 \, a^{3}}{\sqrt {b x + a} b^{4}} + \frac {2 \, {\left ({\left (b x + a\right )}^{\frac {5}{2}} b^{16} - 5 \, {\left (b x + a\right )}^{\frac {3}{2}} a b^{16} + 15 \, \sqrt {b x + a} a^{2} b^{16}\right )}}{5 \, b^{20}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x^3/(b*x+a)^(3/2),x, algorithm="giac")
[Out]
2*a^3/(sqrt(b*x + a)*b^4) + 2/5*((b*x + a)^(5/2)*b^16 - 5*(b*x + a)^(3/2)*a*b^16 + 15*sqrt(b*x + a)*a^2*b^16)/
b^20
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maple [A] time = 0.01, size = 42, normalized size = 0.64 \[ \frac {\frac {2}{5} b^{3} x^{3}-\frac {4}{5} a \,b^{2} x^{2}+\frac {16}{5} a^{2} b x +\frac {32}{5} a^{3}}{b^{4} \sqrt {b x +a}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(x^3/(b*x+a)^(3/2),x)
[Out]
2/5/(b*x+a)^(1/2)*(b^3*x^3-2*a*b^2*x^2+8*a^2*b*x+16*a^3)/b^4
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maxima [A] time = 1.38, size = 56, normalized size = 0.85 \[ \frac {2 \, {\left (b x + a\right )}^{\frac {5}{2}}}{5 \, b^{4}} - \frac {2 \, {\left (b x + a\right )}^{\frac {3}{2}} a}{b^{4}} + \frac {6 \, \sqrt {b x + a} a^{2}}{b^{4}} + \frac {2 \, a^{3}}{\sqrt {b x + a} b^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x^3/(b*x+a)^(3/2),x, algorithm="maxima")
[Out]
2/5*(b*x + a)^(5/2)/b^4 - 2*(b*x + a)^(3/2)*a/b^4 + 6*sqrt(b*x + a)*a^2/b^4 + 2*a^3/(sqrt(b*x + a)*b^4)
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mupad [B] time = 0.05, size = 56, normalized size = 0.85 \[ \frac {2\,{\left (a+b\,x\right )}^{5/2}}{5\,b^4}+\frac {6\,a^2\,\sqrt {a+b\,x}}{b^4}+\frac {2\,a^3}{b^4\,\sqrt {a+b\,x}}-\frac {2\,a\,{\left (a+b\,x\right )}^{3/2}}{b^4} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(x^3/(a + b*x)^(3/2),x)
[Out]
(2*(a + b*x)^(5/2))/(5*b^4) + (6*a^2*(a + b*x)^(1/2))/b^4 + (2*a^3)/(b^4*(a + b*x)^(1/2)) - (2*a*(a + b*x)^(3/
2))/b^4
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sympy [B] time = 2.94, size = 1538, normalized size = 23.30 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x**3/(b*x+a)**(3/2),x)
[Out]
32*a**(45/2)*sqrt(1 + b*x/a)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a
**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) - 32*a**(45/2)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*
a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) + 176*a*
*(43/2)*b*x*sqrt(1 + b*x/a)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a*
*16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) - 192*a**(43/2)*b*x/(5*a**20*b**4 + 30*a**19*b**5*x +
75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) + 39
6*a**(41/2)*b**2*x**2*sqrt(1 + b*x/a)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x*
*3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) - 480*a**(41/2)*b**2*x**2/(5*a**20*b**4 + 3
0*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*
b**10*x**6) + 462*a**(39/2)*b**3*x**3*sqrt(1 + b*x/a)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 1
00*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) - 640*a**(39/2)*b**3*x**3/(
5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9
*x**5 + 5*a**14*b**10*x**6) + 290*a**(37/2)*b**4*x**4*sqrt(1 + b*x/a)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**
18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) - 480*a**(3
7/2)*b**4*x**4/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4
+ 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) + 92*a**(35/2)*b**5*x**5*sqrt(1 + b*x/a)/(5*a**20*b**4 + 30*a**19*
b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x*
*6) - 192*a**(35/2)*b**5*x**5/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*
a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) + 16*a**(33/2)*b**6*x**6*sqrt(1 + b*x/a)/(5*a**20*b
**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5
*a**14*b**10*x**6) - 32*a**(33/2)*b**6*x**6/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b
**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6) + 6*a**(31/2)*b**7*x**7*sqrt(1 + b*x/
a)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*
b**9*x**5 + 5*a**14*b**10*x**6) + 2*a**(29/2)*b**8*x**8*sqrt(1 + b*x/a)/(5*a**20*b**4 + 30*a**19*b**5*x + 75*a
**18*b**6*x**2 + 100*a**17*b**7*x**3 + 75*a**16*b**8*x**4 + 30*a**15*b**9*x**5 + 5*a**14*b**10*x**6)
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